D=1/2(n^2-5n)

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Solution for D=1/2(n^2-5n) equation: 


x in (-oo:+oo)

D = (1/2)*(n^2-(5*n)) // - (1/2)*(n^2-(5*n))

D-((1/2)*(n^2-(5*n))) = 0

(-1/2)*(n^2-5*n)+D = 0

D-1/2*(n^2-5*n) = 0

D-1/2*(n^2-5*n) = 0

D-1/2*n^2+5/2*n = 0

D-1/2*n^2+5/2*n = 0

x belongs to the empty set

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